The equation x^2+y^2=25 defines a circle with center at the origin and radius 5. The line y=x-1 passes through the circle. Using the substitution method, find the point(s) at which the circle and the line intersect.
a. (4,-3) and (-3,4)
b. (3,4) and (-3,-4)
c. (4,3) and (-3,-4)
d. No solution

Question

The equation x^2+y^2=25 defines a circle with center at the origin and radius 5. The line y=x-1 passes through the circle. Using the substitution method, find the point(s) at which the circle and the line intersect.
a. (4,-3) and (-3,4)
b. (3,4) and (-3,-4)
c. (4,3) and (-3,-4)
d. No solution

anonymous · Answer

see he gave a line " y = x -1" and he also said it passes through circle, so just substitute that y value ( which is x -1 right ? ,from line eq), in circle equation and solve that quadratic eqaution for x and then finally 
subtitute those two x values you got by solving that quadratic eqn in the line equation y = x -1 to get the corresponding y values

anonymous · Answer

sorry had to type that much theory , but i hope you get what i'm trying to say :)

anonymous · Answer

Ok, I think I got it. I got (4,-3) and (-3,4) which is a. Is that right?

anonymous · Answer

what are the values of x you got?

anonymous · Answer

because those points you got should also satisfy that line y = x -1 
but your points are not satisfying the line?

anonymous · Answer

I got x=4 and x=-3