Find all polar coordinates of point P where P = ordered pair (5 , pi/3).
hi :DD
the radial lenghth is five and the angle from the x axis is pi/3..is'nt this already in polar co ordinates?
so, obviously, the ordered pair (5, pi/3) works, since that is P. But if you go another 2pi around, you have the ordered pair (5, 7pi/3) which is the same point. in fact, if you find the ordered pair \[(5, (2\pi n)+\pi/3)\] for any integer n, it gets you to the same point
but there's one more thing to consider...
the point (-5, -2pi/3) also works...as seen in the diagram below |dw:1400948068506:dw|
so, the points \[(-5, (2\pi n)-2\pi/3)\] also work.
(5, pi divided by 3 + nπ) or (-5, pi divided by 3 + nπ) (5, pi divided by 3 + (2n + 1)π) or (-5, pi divided by 3 + 2nπ) (5, pi divided by 3 + 2nπ) or (-5, pi divided by 3 + (2n + 1)π) (5, pi divided by 3 + 2nπ) or (-5, pi divided by 3 + 2nπ)
Those are my options
so based on my first set, you can narrow it down to one of the last two, right?
Yes
so of those 2, which seems more likely? if you don't know, it's ok, i just want to see if you can reason it out....
Last one?
so let's consider tha last one...specifically, the second set of the last one, (-5, pi/3 + 2npi) look at the circle i drew and imagine you are standing on the center... you turn so that you are facing pi/3. Now, you walk backwards 5 (walk along the line until you hit the circle...where would you be?
|dw:1400948628668:dw|
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