Question

What is the gravitational energy (relative to the unstretched surface of the trampoline) of the 20 kg ball at its apex 2 m above the trampoline?
What is the kinetic energy of the ball just before impacting the trampoline?
At maximum stretch at the bottom of the motion, what is the sum of the elastic and gravitational energy of the ball?
What conclusions can you draw from the answers found above?
The sumo wrestler originally only jumps 10 cm above the trampoline but he has the same total energy as the ball which was 200 cm higher than the trampoline.

Answer 1

wrong subject i suppose???

Answer 2

That is a very unusual unit for G ( I assume you mean g the acceleration due to gravity)

It is normally expressed as m/s^2 (although the unit you have is dimensionally the same)

Gravitational energy - also known as Potential Energy PE is given by

PE= mgh

You know all the terms - so just multiply them to get PE

Answer 3

There u go

Answer 4

oops
yeah thts for physics

Answer 5

did i help

Answer 6

yeah tht was the first part of the question

Answer 7

When the ball hits the trampoline it has 'lost' the PE that you calculated above.

It starts to stretch the trampoline spring - and CONTINUES to lose PE as it fall below the level of the flat trampoline.

At maximum stretch (x) the ball has fallen h=x

So its loss of PE is mg(h+x)

This energy is stored in the spring (trampoline) and is given by 0.5kx^2

There is no kinetic energy at the max stretch as all is static so

mg(h+x) = 0.5kx^2

If you know k then you can solve for x

Answer 8

there^

Answer 9

dope

Answer 10

dope?

Answer 11

was that not helpful??

Answer 12

no it was

Answer 13

haha okay

Answer 14

can i get a medal :D

Answer 15

yee