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Geometry 20 Online
OpenStudy (anonymous):

find the scale factor of the figure below

OpenStudy (anonymous):

|dw:1400794969827:dw|

OpenStudy (anonymous):

is the distance from D to E 6? and B to C 8? or D to A 6? and C to A 8? either way i can do just need to clarify

OpenStudy (anonymous):

d to e 6 and b to c 8. and can you help me wok it out because i need to no how to do this for my final

OpenStudy (anonymous):

ok so you have a big triangle and a small triangle with the same ratio, meaning one is just a smaller version of the other. so we start by 6+y is the side of the big triangle, and y is the side of the smaller triangle on the same side, similarly for the other side 8 + y+2 is the side for the big triangle and y+2 is the side for the small triangle on the same side now you take the sides of the big triangle and but them in a ratio \[\frac{ 6+y }{ 8+y+2 }\] now you put this equal to the ratio of the small triangle since we put the left side on top of the ratio for the big triangle you do the same with the small triangles ratio \[\frac{ y }{ y+2 }\] then you put them equal to each other and solve for y \[\frac{ 6+y }{ 8+y+2 }=\frac{ y }{ y+2 }\]

OpenStudy (anonymous):

y=6

OpenStudy (anonymous):

how do i solve them equal

OpenStudy (anonymous):

to do these type of problems you should already know how to do that..

OpenStudy (anonymous):

first you cross multiply then you will get a quadratic function

OpenStudy (anonymous):

i got 12/20

OpenStudy (anonymous):

(6+y)(2+y)=y(10+y) y^2+8y+12=y^2+10y y^2 cancels out 8y+12=10y 12=2y y=6

OpenStudy (anonymous):

i thought it was plus ?

OpenStudy (anonymous):

what?

OpenStudy (anonymous):

what did you think was plus?

OpenStudy (anonymous):

oh nevermind

OpenStudy (anonymous):

are you going to give me a medal? @herobeautiful

OpenStudy (anonymous):

sure thanks.

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