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OpenStudy (anonymous):
Find the angle between the given vectors to the nearest tenth of a degree. u = <8, 4>, v = <9, -9>
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OpenStudy (anonymous):
81.6°
25.8°
35.8°
71.6°
OpenStudy (anonymous):
@VeritasVosLiberabit
OpenStudy (anonymous):
so this one may be nice to draw.
OpenStudy (anonymous):
how should i do that?
OpenStudy (anonymous):
You first draw each vector. both vector tails should start from the origin on a cartesian coordinate system.
example:|dw:1400800572041:dw|
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OpenStudy (anonymous):
hmmm alright what's next
OpenStudy (anonymous):
could you show me?
OpenStudy (anonymous):
actually nevermind you can just find the angle between each vector by using the tangent
OpenStudy (anonymous):
here is an example:
|dw:1400800747493:dw|
\[\tan(\theta)=\frac{ x }{ y }\]
\[\theta=\tan ^{-1}(\frac{ x }{ y })\]
OpenStudy (anonymous):
oh alright
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OpenStudy (anonymous):
This is for one vector. Once you have found the angle for one vector do it for the other and add both angles
OpenStudy (anonymous):
im not really sure how to do this though, could u show me with my problem?
OpenStudy (anonymous):
sure
OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
|dw:1400800969045:dw|
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OpenStudy (anonymous):
alright but how do i figure out the angles?
OpenStudy (anonymous):
you know the x and y components for the vectors so use those when you find the relationship with the angle for example:
|dw:1400801088928:dw|
OpenStudy (anonymous):
use this for the first vector, and now you try to find the second angle
OpenStudy (anonymous):
and remember \[\theta=\tan ^{-1}(\frac{ x }{ y })\]
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