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Mathematics 18 Online
OpenStudy (anonymous):

Find the angle between the given vectors to the nearest tenth of a degree. u = <8, 4>, v = <9, -9>

OpenStudy (anonymous):

81.6° 25.8° 35.8° 71.6°

OpenStudy (anonymous):

@VeritasVosLiberabit

OpenStudy (anonymous):

so this one may be nice to draw.

OpenStudy (anonymous):

how should i do that?

OpenStudy (anonymous):

You first draw each vector. both vector tails should start from the origin on a cartesian coordinate system. example:|dw:1400800572041:dw|

OpenStudy (anonymous):

hmmm alright what's next

OpenStudy (anonymous):

could you show me?

OpenStudy (anonymous):

actually nevermind you can just find the angle between each vector by using the tangent

OpenStudy (anonymous):

here is an example: |dw:1400800747493:dw| \[\tan(\theta)=\frac{ x }{ y }\] \[\theta=\tan ^{-1}(\frac{ x }{ y })\]

OpenStudy (anonymous):

oh alright

OpenStudy (anonymous):

This is for one vector. Once you have found the angle for one vector do it for the other and add both angles

OpenStudy (anonymous):

im not really sure how to do this though, could u show me with my problem?

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

|dw:1400800969045:dw|

OpenStudy (anonymous):

alright but how do i figure out the angles?

OpenStudy (anonymous):

you know the x and y components for the vectors so use those when you find the relationship with the angle for example: |dw:1400801088928:dw|

OpenStudy (anonymous):

use this for the first vector, and now you try to find the second angle

OpenStudy (anonymous):

and remember \[\theta=\tan ^{-1}(\frac{ x }{ y })\]

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