Refer to the following conditional statement: If a and b are odd integers, then a + b is an even integer. Which is the converse of the statement? a + b is an even integer If a + b is not an even integer, then a and b are not odd integers. If a and b are not odd integers, then a + b is not an even integer. If a + b is an even integer, then a and b are odd integers.
I suggest you pick actual number for a and b (odd). Lets say for example a = 3 and b = 5.
a + b is an even integer??
In Boolean, If A , then B is expressed \(A\rightarrow B\) so, if converse that boolean, you have \(\neg B\rightarrow \neg A\) Your A is "a and b are odd integers" Your B is "a +b is an even integer" Can you continue now?
Yeah, thanks
np
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