Pre-Calculus: Find a formula for the nth term: Given that a(4)=-12, & a(5)=-6
@Johnbc If you can help, please take a look.
We have the 4th and 5th term so we can easily find the difference
After we have the difference you can use the same method we used last problem to find the A1 term
The difference would be 1/2
\[A_n=A_1 + (n-1)d\]
Yes it did go half or it also went +6
I forgot to mention, but it's geometric. That's also given.
Geometric Sequence\[A_n= A_1 \times r^{n-1}\]
I believe I found the answer, I'll post the steps I used.
|dw:1400808448617:dw| This should be similar to your steps?
Root formula: t(n)=t(1) x r^(n-1) -12=t(1) x (1/2)^(4-1) -12=t(1)(.125) -96=t(1) So, the formula would be "t(n)=-96+(1/2)^(n-1)
Correct!
Alright, thanks again! I may be back with more momentarily.
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