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OpenStudy (noseboy908):
Pre-Calculus: Find a formula for the nth term: Given that a(4)=-12, & a(5)=-6
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OpenStudy (noseboy908):
@Johnbc If you can help, please take a look.
OpenStudy (anonymous):
We have the 4th and 5th term so we can easily find the difference
OpenStudy (anonymous):
After we have the difference you can use the same method we used last problem to find the A1 term
OpenStudy (noseboy908):
The difference would be 1/2
OpenStudy (anonymous):
\[A_n=A_1 + (n-1)d\]
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OpenStudy (anonymous):
Yes it did go half or it also went +6
OpenStudy (noseboy908):
I forgot to mention, but it's geometric. That's also given.
OpenStudy (anonymous):
Geometric Sequence\[A_n= A_1 \times r^{n-1}\]
OpenStudy (noseboy908):
I believe I found the answer, I'll post the steps I used.
OpenStudy (anonymous):
|dw:1400808448617:dw| This should be similar to your steps?
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OpenStudy (noseboy908):
Root formula: t(n)=t(1) x r^(n-1)
-12=t(1) x (1/2)^(4-1)
-12=t(1)(.125)
-96=t(1)
So, the formula would be "t(n)=-96+(1/2)^(n-1)
OpenStudy (anonymous):
Correct!
OpenStudy (noseboy908):
Alright, thanks again! I may be back with more momentarily.
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