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Chemistry 8 Online
OpenStudy (anonymous):

how do i find limiting reagent for this problem?

OpenStudy (azureilai):

You first write out the chemical reaction, then calculate how much of each substance is required to make C2H3Cl. The answer should be C2H2

OpenStudy (azureilai):

OpenStudy (anonymous):

I still dont understand the process of "how much of each substance is required to make C2H3Cl" i just follow some steps online aand i end up with HCl as my limiting reagent. Maybe i am wrong. but thank you for your response Azureilai and wow taking time to have a attachment :D i appreciate your help

OpenStudy (anonymous):

but your attachment is clear so do i have to apply this to any similar question and the lowest value will be my limiting?

OpenStudy (azureilai):

Yeah so basically what I calculated was how much product can be produced with the specific amount of reactants provided. Since C2H2 had the lower amount, it means C2H2 can only make .192 mole of C2H3Cl which is less than the .274 mole produced by 10g of HCl. Therefore, it means C2H2 is the limiting reagent

OpenStudy (azureilai):

glad to be of help

OpenStudy (anonymous):

thank you :D

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