Quick math question! Will Medal!
Basically we just have to add the areas of a bunch of rectangles and triangles
Do you know the formula for the area of a triangle?
\[area = \frac{ 1 }{ 2 }bh\]
First lets find the area of the triangle on top, that would be: \[\frac{ 1 }{ 2 }(3)(2.6)\]
That's 3.9, right?
Yep, and since there's actually an identical triangle on the bottom of the figure, we can add that if we simply don't multiply by 1/2
So the area of both the top and bottom triangles combined is 7.8 because they're both 3.9
So now we can add the area of the two rectangles in front
Area of a rectangle is just: \[length \times width\]
so 7 x 3 is?
21!
And there's a second rectangular face just like it on the other side, so 21 * 2?
42..
Oh and actually the third rectangle in the back is also the same, so plus another 21
So the area of the triangles is 7.8m^2 And the area of the rectangles is 63m^2 so 63^2 + 7.8m^2 would be the answer
If it's simplified that is
\[70.8\]
Yep :)
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