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Mathematics 15 Online
OpenStudy (anonymous):

Divide. Assume that no denominator equals zero.

OpenStudy (anonymous):

sorry @Jackienvdm last one

OpenStudy (anonymous):

Flip the right side so that it turns into a multiplication problem. \[8d ^{3} \div 6c \times 24 \div c ^{3}d ^{4}\] From here, cancel out what you can. |dw:1400820805429:dw| The restrictions are: \[c \neq 0\] \[d \neq 0\]

OpenStudy (anonymous):

So it would be B.

OpenStudy (anonymous):

oh,thanks and can i get help on just two more questions? @Jackienvdm

OpenStudy (anonymous):

Go ahead. (:

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

Divide and simplify completely. Assume that no denominator equals zero.

OpenStudy (anonymous):

@Jackienvdm

OpenStudy (anonymous):

So flip the right side and factor out the binomials. |dw:1400821425485:dw| Restrictions: \[d \neq 0, -1\]

OpenStudy (anonymous):

Yup so it would be A.

OpenStudy (anonymous):

oh,thanks

OpenStudy (anonymous):

last one

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