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OpenStudy (anonymous):
Integral calculus help please. How do you use the FTC (part 1) when both a and b have x?
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OpenStudy (anonymous):
you would just use it as you normally would
OpenStudy (anonymous):
treat those values as a and b
OpenStudy (anonymous):
The first fundamental theorem of calculus?
hartnn (hartnn):
you need to find the derivative of that integral ?
OpenStudy (anonymous):
That was my next question
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hartnn (hartnn):
\(\Large \dfrac{d}{dx}\int \limits_{f(x)}^{g(x)}h(x)dx = H(g(x))g'(x)-H(f(x))f'(x)\)
hartnn (hartnn):
basically you will need to use the chain rule
hartnn (hartnn):
since here g(x) = x
g'(x) = 1 only
hartnn (hartnn):
but f(x) is a function of x,
so you need to find f'(x)
f(x) = sqrt x
hartnn (hartnn):
did u get what to do ?
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hartnn (hartnn):
good, if you want me to verify your final answer, tell us what u got :)
OpenStudy (anonymous):
would it not be \(h(g(x))g'(x)-h(f(x))f'(x)\)? with capital H it just makes me think it's an anti-derivative
hartnn (hartnn):
^ thats correct
sorry for the confusion
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