A 2.20kg block on a horizontal floor is attached to a horizontal spring that is initially compressed 0.0380m . The spring has force constant 900N/m . The coefficient of kinetic friction between the floor and the block is 0.41 . The block and spring are released from rest and the block slides along the floor.
What is the speed of the block when it has moved a distance of 0.0180m from its initial position? (At this point the spring is compressed 0.0200m .)

Question

A 2.20kg block on a horizontal floor is attached to a horizontal spring that is initially compressed 0.0380m . The spring has force constant 900N/m . The coefficient of kinetic friction between the floor and the block is 0.41 . The block and spring are released from rest and the block slides along the floor.
What is the speed of the block when it has moved a distance of 0.0180m from its initial position? (At this point the spring is compressed 0.0200m .)

anonymous · Answer

Not sure if this is right but you can take a look and see what you think:
$$|F _{net}|=-kx+muN=-(900)(.038)+(.41)(2.2*9.8)=25.36N$$
$$a=\frac{ F }{ m }\rightarrow a=\frac{ 25.36 }{ 2.2 }=11.5\frac{ m }{ s ^{2} }$$
$$v _{f}^{2}=v _{i}^{2}+2a \Delta x \rightarrow v _{f}^{2}=0+2(11.5)(.018)$$
$$vf=\sqrt{.414}=.64\frac{ m }{ s }$$

anonymous · Answer

Okay thank you very much!!

anonymous · Answer

please don't take this as correct, just use this as a guide because I'm pretty sure its wrong

anonymous · Answer

Yeah sure , but thanks for trying ^-^

anonymous · Answer

No problem, if you'd like to post your work or have any ideas on what range the answer is in we may be able to figure it out

anonymous · Answer

Okay