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Calculus1 11 Online
OpenStudy (anonymous):

Hyperbolic functions

OpenStudy (anonymous):

OpenStudy (anonymous):

so sinh(x) is defined as \[\sinh(x)=\frac{ e ^{x}-e ^{-x} }{ 2 }\] \[\frac{ 5 }{ 4 }=\frac{ e ^{x}-e ^{-x} }{ 2 }\] \[\ln(\frac{ 5 }{ 2 })=\ln(e ^{x}(1-e ^{-2x}))\] \[\ln(\frac{ 5 }{ 2 })=xln(1-e ^{-2x})\] need to think for a moment getting stuck on combining x's

OpenStudy (anonymous):

\[\ln(\frac{ 5 }{ 2 })=x+\ln(1-e ^{-2x})\]

OpenStudy (anonymous):

\[\sinh(x)=-isin(ix)\]

OpenStudy (anonymous):

\[\ln(\frac{ 5 }{ 2 })=x+\ln(\frac{ e ^{2x} }{ e ^{2x} }-\frac{ 1 }{ e ^{2x} })\] \[\ln(\frac{ 5 }{ 2 })=x+\ln(\frac{ e ^{2x}-1 }{ e ^{2x} })\] \[\ln(\frac{ 5 }{ 2 })=x+\ln(e ^{2x}-1)-2x\] \[\ln (\frac{ 5 }{ 2 })=\ln(e ^{2x}-1)-x\] i'm trying to get x isolated may need to think hard about this one

OpenStudy (anonymous):

\[asinh(x)=\ln(x+\sqrt{x+1})\] \[x=asinh(\frac{ 5 }{ 4 })\] \[x=\ln(\frac{ 5 }{ 4 }+\sqrt{\frac{ 5 }{ 4 }+1})\] from the equation x~1

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