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Mathematics 8 Online
OpenStudy (meilendurcer):

The table below shows the values of f(n) for different values of n: A. f(1) = 1, f(2) = 2, f(n) = f(n -1) f(n - 2); n > 2 B. f(1) = 1, f(2) = 2, f(n) = f(n -1) + f(n - 2); n > 2 C. f(1) = 1, f(2) = 2, f(n) = f(n -3) + f(n - 2); n > 2 D. f(1) = 1, f(2) = 2, f(n) = f(n -3) f(n - 2); n > 2

OpenStudy (meilendurcer):

OpenStudy (meilendurcer):

@navk can you help?

OpenStudy (anonymous):

You can clearly identify a pattern in the table in the row for f(n); After n = 2, every value of f(n) is a product of its two previous values. For example, f(3) = 2 = 2 * 1 = f(2) * f(1) and f(4) = 4 = 2 * 2 = f(3) * f(2). f(n) can be defined as f(n) = f(n-1)f(n-2)

OpenStudy (meilendurcer):

right yeah. so it's between A and B?

OpenStudy (meilendurcer):

I would say A after looking at the equation for a while

OpenStudy (anonymous):

Yes its A. Good!

OpenStudy (meilendurcer):

whoooo!!

OpenStudy (meilendurcer):

thanks!!

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