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Mathematics 7 Online
OpenStudy (anonymous):

The population of a town is 81,712 and declines continuously at a rate of 4.1% each year. What is the approximate population of the town in 17 years?

OpenStudy (anonymous):

Will give medal!!!!!!

OpenStudy (anonymous):

This will use the formula for exponential decay

OpenStudy (anonymous):

\[P=P _{0}e ^{rt}\]

OpenStudy (anonymous):

can you please help explain in words?

OpenStudy (anonymous):

what do i plug it into??

OpenStudy (anonymous):

\[P=81712e ^{-(.041*17)}\]

OpenStudy (anonymous):

I just plugged in all the values for you into the equation I pasted earlier

OpenStudy (anonymous):

whats the e for ?

OpenStudy (anonymous):

all you have to do is solve on the caluclator and the value of P will give you the approximate population in 17 years

OpenStudy (anonymous):

e is euler's constant or the exponential growth constant

OpenStudy (anonymous):

e~2.71828 if you don't have it on your calculator

OpenStudy (anonymous):

so do i raise e by .041*17?

OpenStudy (anonymous):

yes and multiply it by the negative for decay

OpenStudy (anonymous):

i got -154,815..... thats not right....

OpenStudy (anonymous):

no check your math again

OpenStudy (anonymous):

JK!!!!! i got 40,698

OpenStudy (anonymous):

try multiplying .041 and 17 and -1 first then raise it over e

OpenStudy (anonymous):

well done thats it

OpenStudy (anonymous):

so what about The population of a city is 83,945 and grows continuously at a rate of 1.3% each year. What is the approximate population of the city in 21 years?

OpenStudy (anonymous):

so for this one you want to solve the same way except use a positive value for the exponential power

OpenStudy (anonymous):

\[P=83945e ^{.013*21}\]

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