Question

help got the aster to the first part of the question need help with the second part

Answer 1

second part is Being a smart financial planner, you want to figure out how many months it will be until your principal is paid down to $10,000.00. Solve for t and show all of your work. Note that t will be negative because the number of months will decrease the principal the answer to the first part isA(t)=39145(1+0.03/12)^12t

Answer 2

someone please help if you can this is really late

Answer 3

set A(t) = 10,000 and solve for t

Answer 4

\[\log _{(1+\frac{ 0.03 }{ 12 })}\frac{ 10000 }{ 39145 }\frac{ 1 }{ 12 }=t\]

Answer 5

ok one sec let me do the math really quick

Answer 6

for the logarithm you can use change of base formula \[\frac{ \ln(\frac{ 10000 }{ 39145 }\frac{ 1 }{ 12 }) }{ \ln(1+\frac{ .03 }{ 12 }) }=t\]

Answer 7

the equation should also be negative I am not getting a reasonable number right now though

Answer 8

so is it 0.239? i don't think I did it right but I am not sure

Answer 9

my answer comes out as 1542 years

Answer 10

or months

Answer 11

so 128 years

Answer 12

I don't think this is correct

Answer 13

so the 0.239 would be -0.239 if it is correct

Answer 14

I'm not getting the right answer either I don't think. My equation should also have a negative vvalue for t

Answer 15

ya neither do I

Answer 16

Not sure about this once. I don't see where else there could be an error
The equation should be\[\frac{ \ln(\frac{ (12)39145 }{ 10000 }) }{ \ln(1+\frac{ .03 }{ 12 }) }=t\]

Answer 17

n is 12 so if it was 1n wouldn't be 1(12) which is 12

Answer 18

Im not sure what n is. Maybe paste the whole problem

Answer 19

It won't let me