I really need help! What is the slope of the line? http://static.k12.com/calms_media/media/1417000_1417500/1417242/1/78bd85d6763d76c1b7292055c9bcc3f181e566e1/MS_PA_130905_170048.jpg A:-1/7 B:1/7 C:-1 D:1
Do you know the formula for slope?
Isn't it (x2*y2) and (x1*y1)?
\[\frac{ y _{2} - y_{1} }{ x_{2} - x_{1} }\]
(-5, 4) x1, y1 (2, -3) x2, y2 So you're going to plug those values into the formula
Ohh so it's -5-2/4-(-3)=-1?
I think you did it backwards. x1 = -5 x2 = 2 y1 = 4 y2 = -3
then it's -5-4/2-(-3)=-1.8?
The slope is -1. You did it correctly
The points are interchangeable. (-5,4) doesn't have to be point 1
Also, another way to find the slope is to look at the graph
When you move once to the left, you move once up
slope = rise/run slope = -1/1 slope = -1
He was correct but he did it incorrectly. If it had been any other value he would have been wrong, because he put the x-values in where the y-values should have gone.
Ya you can make point 1 and point 2 whichever you want. Just don't mix them up like you do when you wrote n it's -5-4/2-(-3)=-1.8?
Oh, wait I did it wrong? And I'm female.
The first attempt you did it correctly. This part you didn't do correctly because you mixed up the x's and y's.
Yes, but my point is, you made the formula look like this: x2-x1/y2-y1 The formula is y2-y1/x2-x1
Sure but you can assign (x1,y1) to any point on the graph. Doesn't have to be one particular point
and (x2,y2)
I see then
No, she did the process incorrectly the first time because she stuck the x-values in the y-places. The only reason why she got it right is because it came out to -1
I'm not saying that you can't reverse them, I'm saying you can't put any x-value into the numerator and expect to get the right answer
Oh
Ahiru Ohh so it's -5-2/4-(-3)=-1? You could do (-5, 4) x1, y1 (2, -3) x2, y2 or (-5, 4) x2, y2 (2, -3) x1, y1 But you plugged in x-values for the numerator
Oh ok! So it should only be x,y instead of x,x or y,y?
Yes. The points are always (x, y) values
So it'll look like (x, y) (x, y) And you can put these in either order using the slope formula, so long as the numerator has the y-values and the denominator has the x-values
Kk, but how do you know when to use - or +?
As in when you have two negative numbers?
No like this equation how did you know to subtract x,y and not add?
It's just the formula. If you have this: 3-(-4), the rules of algebra say it will be 3+4 because two negatives make a positive
Alright, thank you so much for all your help!!
You're welcome!
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