Question

Eliminate the parameter.

x = 5t, y = t + 8

Answer 1

find t from one eq . and put in the second eq.

Answer 2

In order to eliminate the parameter t, you are basically putting the y equation in terms of x. We can do this since we know that x = 5t. So what is t in terms of x? (Hint: divide both sides by the 5)

Answer 3

so were rewriting the equation, but how ? @thechocoluver445

Answer 4

Since you know that x = 5t, you also know that t = 5/x.
You can substitute that 5/x in for t in the second equation, y = t + 8.

Answer 5

(That's what my hint was referring to but I guess it was a little unclear, sorry)

Answer 6

y=-8 ?

Answer 7

t=y-8
put in other.

Answer 8

y = 5x + 8

y = x divided by five + 8

y = 5x - 8

y = x divided by five - 8

these are my answer choicews

Answer 9

@surjithayer, when they are asking you to get rid of the parameter they mean leave the equation in terms of y and x, and not t

Answer 10

x=5(y-8)

Answer 11

The second option is correct, then. @Zaria602, do you understand now?

Answer 12

Oops my drawing is wrong! It should read (x/5)!!

Answer 13

t = x/5! I also messed that up in my replies above, so sorry!

Answer 14

kinda i dont understand how you are switching the x and t

Answer 15

So you're given the equation x =5t. If you divide both sides by 5, you get that

\[x = 5t\]
\[\frac{ x }{ 5 } = \frac{ 5t }{ 5 }\]
\[\frac{ x }{ 5 } = t\]

Answer 16

Then you have the equation y = t +8

Since \[\frac{ x }{ 5 } = t\] you can substitute that in for t.

Thus, you get

\[y = t +8\]
\[y = \frac{ x }{ 5 } + 8\]

Answer 17

Eliminate the parameter.

x = t2 + 2, y = t2 - 4

so how would it work with this question

Answer 18

The squares may seem a little scary, but you don't have to worry about taking the sqaure root or anything like that because t^2 shows up in the y equation too.

Instead of finding t in terms of x, you find t^2 since it's in the y equation as well.

So you do a similar substitution:

\[x = t^2 + 2\]
Subtract 2 from both sides.
\[x -2 = t^2\]

And then you substitute that x -2 in for t^2 in the equation y = t^2 -4.

\[y = t^2 -4\]
\[y = x-2 - 4\]
You can simplify this to
\[y = x - 6\]

Answer 19

y = x - 6, x ≥ 1

y = x + 6, x ≥ 1

y = x2 - 6, x ≥ 1

y = x2 + 6, x ≥ 1

these are my answer choices

Answer 20

So it would be the first choice. The x >_ 1 is because of the x being squared.