Question

the radius of the circle 2x² + 2y² - 3x + 4y - 1 = 0
a. √ 33
4
b. 33
16
c. √ 33
3
d. 17

please help me to get it. i need you solutions.

Answer 1

What do you think the answer is?

Answer 2

b?

Answer 3

justify your answer. don't guess

Answer 4

ok i don't know how to get the real answer. so please help me to know that.

Answer 5

Remember the equation of a circle. (x-h)^2 + (y-k)^2 = r^2

Answer 6

manipulate the equation so that it fits this format. Then you will see the radius

Answer 7

do you know how to make a perfect square?

Answer 8

how can i apply the formula in the question?

Answer 9

ok, take steps, you do, I guide, deal?

Answer 10

ok men.

Answer 11

if I re-arrange the given equation on this way, is it ok to you?
\[2x^2-3x+2y^2+4y-1=0\]

Answer 12

sure

Answer 13

now, I just take the x part only (don't worry, I will not let y free, just do later)
\[2x^2 -3x\]
to get this part become a perfect square, do you know how to do?

Answer 14

no, i don't what will i do.

Answer 15

but will try to listen just to understand

Answer 16

x² - 3/2x = 0
x² - 3/4x = (- 3/4)²
(x - 3/4)² = 9/16
x - 3/4 = 3/4 ?

Answer 17

nope, I am trying to make it as simple as possible to explain you. Wait, I will not let you alone

Answer 18

ohh thank you so much bro! i'll appreciate your kindness.

Answer 19

bro?

Answer 20

I am writing out, will scan and post after finish.

Answer 21

ooh thanks men! I hope I can return the favor some day.

Answer 22

finally!!!

Answer 23

If you don't understand at somewhere, just make questions
hihihi...

Answer 24

so the final asnwer is 33 over 16?

Answer 25

\[\dfrac{\sqrt{33}}{4}\]

Answer 26

thanks men!