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Mathematics 21 Online
OpenStudy (alina123):

Tadika has a gift to wrap. Both of these containers will hold her gift. a) Which container would allow her to use the least amount of wrapping paper? Triangular prism- SA= 770 Rectangular prism- SA= 1,000 b) According to your answer for part a, if the wrapping paper that was bought had dimensions of 77.8 cm by 9.76 cm would Tadika have enough paper to use the container you picked? Dont you multiply the dimensions and see whether it is big or small enough for the container? @Loser66 @iPwnBunnies

OpenStudy (loser66):

I don't understand what the SA is

OpenStudy (alina123):

surface area

OpenStudy (loser66):

surface area?

OpenStudy (alina123):

yeh

OpenStudy (loser66):

so, why are you stuck? is it not that 770 < 1000?

OpenStudy (alina123):

so, she could sue the triangular prism

OpenStudy (alina123):

*use*

OpenStudy (loser66):

yes

OpenStudy (alina123):

what about number 2

OpenStudy (loser66):

is it that hard? just area of the wrap paper. times the dimensions together, you have the area of the WRAPPAPER is 77.8*9.76= 759.328 while the BOX is 770, tell me, it is enough for her to wrap the box by that paper?

OpenStudy (loser66):

what do you mean by yup? 759< 770, she can't use that paper to wrap the box

OpenStudy (alina123):

oh i thought the wrapping paper didn't fit the box

OpenStudy (loser66):

yes, you are correct, the wrapping paper didn't fit the box; it's smaller than the box

OpenStudy (alina123):

ok well thanks again for the help! just getting homework done on friday so my weekend is free.

OpenStudy (loser66):

ok

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