Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

Help appreciated! At noon, ship A is 50 nautical miles due west of ship B. Ship A is sailing west at 17 knots and ship B is sailing north at 19 knots. How fast (in knots) is the distance between the ships changing at 3 PM? (Note: 1 knot is a speed of 1 nautical mile per hour.)

OpenStudy (shamim):

c my attachment

OpenStudy (shamim):

OpenStudy (shamim):

feel free to ask if any confusion

OpenStudy (anonymous):

im a little confused by the drawing, I see the graph, its the formulas u used that I don't understand

OpenStudy (shamim):

right angle triangle

OpenStudy (shamim):

pithagorean theorem

OpenStudy (shamim):

hypotenuse ^2=base^2+oposit^2

OpenStudy (anonymous):

So ur telling me basically that if I find the solution to the Pythagorean , I will have the answer to the question

OpenStudy (shamim):

A2B1B2 is a right angle triangle

OpenStudy (shamim):

we need to find out the value of A2B2

OpenStudy (shamim):

ship A goes frm A1 A2

OpenStudy (shamim):

ship B goes frm B1 to B2

OpenStudy (shamim):

the distance between ship A nd ship B at 3 pm is A2B2

OpenStudy (shamim):

need to find out A2B2

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!