The exponential decay graph shows the expected depreciation for a new boat, selling for $3500, over 10 years. a. Write an exponential function for the graph. b. Use the function in part a to find the value of the boat after 9.5 years. 
There's an equation for exponential growth and decay, you remember what it was?
i think its y=c*e^rt ?
Or you can also use the equation y=ab^x x = time, a = initial amount, and b = rate of exponential growth. y = ab^x a = 3500 when x=3, y = 1500 1500 = 3500b^3
the equation y=ab^x is easier to comprehend in my opinion
and from there solve for b
oh okay. because when i was working it out i was getting lost on my problem. so thank you.
what would the answer for be for b?
after solving the equation for 1500 = 3500b^3 you'll get the answer for b from there y = 3500(the answer for b)^9.5 x = time which is 9.5 for the second part
so would it be, y=3500(3/7)^9.5 or y(9.5)=3/7?
\[b =\sqrt[3]{\frac{ 3 }{ 7 }}\]
which is 0.753947441 in decimal form
y=ab^x for part b y = 3500(0.753947441)^9.5
that equals to?
so that would be the exact answer? with the decimal being that long?
whoops didn't see the last part. okay hold on
you're basically solving the outcome of that equation for part b
so 238.226?
i meant, 239.226
for part A, in the graph where i looked at year 3, the amount is 1500 so by using the equation y=ab^x x is time, and for x i got 3 when x=3 y is therfore 1500 1500 = 3500b^3 the initial amount in (a) stays the same and yes you are correct, its 239.226
yay! so b is 239.226?
if so thank you so much for your help!
You're Welcome :)
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