Question

im stuck
! Write the equation of the line that is parallel to the line 4x - 3y = -12 and passes through the point (-3, 4)

Answer 1

use the slope-intercept formula: y=mx+b
slope (m) should be the same for parallel lines. The variable that changes is b (y-intercept).
first write the equation is terms of
(-12-4x)/3=y
y=(-4/3)x+b
plug in the points (-3,4) for x and y then solve for b
b=0, therefore
the equation for the paralell line is
y=(-4/3)x

Answer 2

but the options are
a. y=4/3x+8
b.y= 4/3x+3
c. y=-3/4x+8
d. y=-3/4x+3
the addiction parts is what i dont get.

Answer 3

ok hold on let me check my math

Answer 4

ok

Answer 5

i got y=-4/3+4

Answer 6

ah yes the first line simplifies to \[y=\frac{ 4 }{ 3 }x+4\]

Answer 7

but why would you get rid of the negetive sign ?

Answer 8

so that means the equation for the parallel line should be
\[y=\frac{ 4 }{ 3 }x+b\]
plug in (-3,4) gives
\[8=b\]
\[y=\frac{ 4 }{ 3 }x+8\]

Answer 9

@thaliluvsya ok hold on let me write up all of the steps for you

Answer 10

ok thank you because i dont get it.

Answer 11

\[4x-3y=-12\]
\[-3y=-12-4x\]
\[y=\frac{ -12-4x }{ -3 }\]
\[y=\frac{ -12 }{ -3 }+\frac{ -4x }{ -3 }\]
\[y=4+\frac{ 4 }{ 3 }x\]

Answer 12

this is how I get the line equation for the first line you are given. Do you understand how I get the parallel line?

Answer 13

i get it just why would you add a negetive sign in front of the 4x behind the 12?

Answer 14

and would you mind helping me in a few more? just 3