Question

Someone please please help me...

Answer 1

@VeritasVosLiberabit

Answer 2

\[A(t)=Pe ^{rt}\]
\[100=50e ^{.05t}\]
\[\ln(\frac{ 100 }{ 50 })=\ln(e ^{.05t})\]
\[\ln(2)=.05t\]
\[\frac{ \ln(2) }{ .05 }=t\]
t=13.9 years

Answer 3

Does this make sense?
P is the starting quantity and A(t) is the final. r is the rate and t is time

Answer 4

Yes it does o:

Answer 5

Help me with this one too?

Answer 6

Sure make a new thread