Question

What's the solution?

y > x-2
y <= (less than and equal to) -(1/3)x+3

Answer 1

treat it like a equals sign but flip it if you ever multiply or divide by a negative number

Answer 2

for the first one
\(y>x-2\implies y\color{red}{+2}>x-2\color{red}{+2}\implies y+2>x\)

Answer 3

Why did you add 2 to both sides?

Answer 4

\[y >x-2\]
\[y \le -\frac{ 1 }{ 3 }x +3\]

What's the solution ^

Answer 5

because you want to get x by itself.
it is very much like this y=x-2
if we solve for x we add 2 to both sides.

Answer 6

what do we do with the second equation then?

Answer 7

\(y\le-\frac{1}{3}x+3\)

subtract 3 from both sides
\(y-3\le\frac{1}{3}x\)
multiply both sides by 3
\(3(y-3)\ge x\)

Answer 8

I need to find the solution of the system

Answer 9

the system being those two inequalities

Answer 10

>.< sorry if i'm being very confusing

Answer 11

ohh i need to find the value of x c:

Answer 12

Do you have a answer choice?

Answer 13

I got y+2>x for the first
I got y<=3-x/3 for the second

Answer 14

3y-9=>x
is what @zzr0ck3r wanted to say in his equation

Answer 15

no answer choices

Answer 16

you do know that there is more then 1 solution

Answer 17

So was I right?

Answer 18

I would probably graph each inequality and the solutions will be in the overlapping sections

Answer 19

@texaschic101
I'm suppose to show it algebraically.

Answer 20

y>x-2
y<=-(1)/(3)*x+3

Since x is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.
x-2<y or y<=-(1)/(3)*x+3

Move all terms not containing x to the right-hand side of the inequality.
x<y+2 or y<=-(1)/(3)*x+3

Since x is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.
x<y+2 or -(1)/(3)*x+3>=y

Multiply -(1)/(3) by x to get -(x)/(3).
x<y+2 or -(x)/(3)+3>=y

Move all terms not containing x to the right-hand side of the inequality.
x<y+2 or -(x)/(3)>=y-3

Multiply each term in the inequality by 3.
x<y+2 or -x>=3y-9

Multiply -x by -1 to get x.
x<y+2 or x<=3y*-1-9*-1

Divide each term in the inequality by -1.
x<y+2 or x<=-3y+9

Hope this helps. This is the Union of the inequalities. You could also take a look at this: http://www.wolframalpha.com/input/?i=y%3Ex-2%2Cy%3C%3D-%281%2F3%29x%2B3