Question

Please help with one question! will Fan and medal!

Skip designs tracks for amusement park rides. For a new design, the track will be elliptical. If the ellipse is places on a large coordinate grid with its center at (0,0), the equation x^2/2500+y^2/8100=1 models the path of the track. The units are given in yards. How long is the major axis of the track? Explain how you found the distance.

Answer 1

90

Answer 2

Can you please explain how you got that answer?

Answer 3

@eHoaX

Answer 4

anyone?

Answer 5

look at these 2 pics from Mr.google

Answer 6

in the first one h and k are both zero's because the center of the elipse is (0,0)
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the major axis is the length of the widest part of the elipse, here is is on the x-axis, sometimes depending how they draw the elipse it could be on the why axis
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in your eliptical formula what is the value of "a" and "b" if we wrote like this - given that h and k are zeros because the center of the elipse is 0,0 ?
\[\frac{ x ^{2} }{ a ^{2} } + \frac{ y ^{2} }{ b ^{2} } = 1\]

Answer 7

@ganeshie8 hey buddy, see u r online :) , can I please ask u to verify the above answer if u got some time...please?

Answer 8

thanks @ganeshie8 ;)

Answer 9

lol this notation stuff of a and b is very tricky..
major axis is always the longest segment :
a = 90 since 90 > 50
so major axis = 2a = 2*90

Answer 10

its a vertical ellipse wid major axis along y-axis, so the equation wud be :
\(\large \dfrac{x^2}{b^2} + \dfrac{y^2}{a^2} = 1\)

this is valid if we fix our notations for \(\large a\) to be major axis..

Answer 11

i always get confuse between a and b, i think the simple way to remember is :
long = major
short = minor

Answer 12

DAMN!!! u r 100% correct @ganeshie8
I got caught out here, thanks buddy
I'll delete my above wrong answer
so the answer is 180 , double what @eHoaX had, he was also on the right track ...almost..