Compare the functions below?
Is it B?
This is a problem that requires you to look at the graph and the data table. As you can see, the values for g(x) in the y column are all negative. while f(x) has values that have positive y-values (eg. when x=pi, y = 3)
I looked at the graph and data table and got B?
Oh I didn't see h(x) let me take a look again
Ok the answer isn't B
You can knock out g(x) since it has y-values that are all negative. Compare f(x) and h(x)
These functions will have maximum y-values when their respective trig components = 1
f(x)
not quite
see where sin(x) and cos(x) =1 for both functions. Look at the graph for f(x), plug in a coordinate for h(x)
first off what is the maximum y value for f(x) according to the graph?
So the answer is D?
yes but why?
Can you explain though because I need to show my work
Look at the graph. What is the max value shown for y?
Wait they are the same right?
No they aren't
so? what is the maximum y-value for f(x)?
What? I am not sure. Can you explain all this to me?
just from the graph shown
If you look at pi what value can be seen on the y-axis?
3
yes
So now you know that f(x) has a maximum value of 3 for y
since it is the largest y-value shown on the graph
Now compare it with h(x) You know that h(x) has a trig function in it, cos(x). This will have a maximum y-value when cos(x)=1 since the trig function can only take values from (0,2npi) according to the x-axis labelled on the graph
set cos(x)=1 and what value do you get for h(x)?
Yes, and?
I actually have two questions that one and this one, I need to show work for both
You still didn't finish this one. what value do you get when you set cos(x)=1?
1.85
no I don't mean plug 1 into x. cos(x) becomes 1
so the equation turns into 2(1)+1
Okay so what do I put to show my work?
And what about second one?
What is the answer you get when you substitute cos(x)=1 into h(x)?
I don't know this is taking a long time
It can take as long as it needs. 2(1)+1=?
If you'd like to understand you need to go through the steps so you can show your work.
I will just try finding it
HelP?
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