Question

Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis.

y = –2x2 + x + 3

Answer 1

ooo i hated parabolas): haha i was told close but dont touch

Answer 2

haha, I am learning it

Answer 3

i learned it like 3 months ago and getting ready to take finals
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Answer 4

that is -2x squared right

Answer 5

mmhmm

Answer 6

y = –2x^2 + x + 3

Answer 7

hold on a sec i might be able to link some notes on here

Answer 8

Put it into slope intercept form, then you can see which way it's opening, and its vertex.

Answer 9

You can also use the discriminant.

Answer 10

I am going to use Slope form

Answer 11

yea what he said i didnt learn with disciminant batman

Answer 12

It's fine, just use what you're comfortable with :)

Answer 13

but if you want to try it discriminint equation is b^2-4ac if im not mistaking is that what your equation is batman

Answer 14

y = mx + b.. soo
y=..wait what... can you help me @iambatman

Answer 15

if you have notes it can help

Answer 16

Can u help @Loser66

Answer 17

just solve the right hand side (let it =0). You can use either discriminant or factor, you will get 2 points cut the x-axis.

Answer 18

http://hhs.tsc.k12.in.us/webpages/teacherpages/teachers/mvglynn/Algebra%201/Ch.%209/Graphing%20Parabolas.pdf




go to this website directly

Answer 19

this is what i had to use provided from my teacher himself

Answer 20

the parabola is an downward one (a <0) --> the vertex is above the points

Answer 21

A.no points in common; vertex below x-axis
B.2 points in common; vertex above x-axis
C.1 point in common; vertex on x-axis
D.2 points in common; vertex below x-axis

So it is B or D right?

Answer 22

yup

Answer 23

So it is B?

Answer 24

pretty much go to my link if need be

Answer 25

k

Answer 26

Ty @Loser66

Answer 27

np

Answer 28

http://hhs.tsc.k12.in.us/webpages/teacherpages/teachers/rlmckee/9.1%20graphing%20parabolas.pdf