Question

If an object is thrown directly upwards (initial speed 3m/s) and the only other force acting on it is gravity (9.8m/s) what is the maximum height it will reach?

Answer 1

I assume you know the equations for constant acceleration

v=u+at
v^2=u^2+2as
s=ut+0.5at^2

In this case you know that u = 3m/s,
its maximum height will be achieved when v=0
you know a = -9.8m/s^2
(it is NEGATIVE because the velocity is being measured as positive in UP direction, but acceleration of gravity is positive in a downward direction)

so you know u,v,a

Choose the equation above that will let you solve s

Answer 2

\[h = Vit + \frac{ 1 }{ 2 }g t ^{2}\]

Answer 3

for upward movement of body g = -g

Answer 4

@IhteshamMalik
That is not the best equation - t is not known

Answer 5

\[2gh = Vf ^{2} - Vi ^{2}\]

Answer 6

Now - it would be good if the OP solved it for himself.....

Answer 7

Vi = 3 m/s g = -g Vf = 0 so,
hmm next OP can solve himself...