Question

HOW WOULD I SOLVE; r^+2r-33=0?

Answer 1

Is the equation supposed to be
\[r ^{2}+2r-33=0\]

Answer 2

If so, I don't think there are any any simple factors for the equation so you should use the quadratic equation
\[\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]

Answer 3

\[a=1,b=2,c=-33\]
a,b,c corresponds to the coefficents of each term within the form
\[ax ^{2}+bx+c=0\]

Answer 4

\[r^2+2r-33=0\]\[r^2+2r=33\]\[r^2+2r+1=33+1\]\[(r+1)^2=34\]take it from here.

Answer 5

yeah I meant r squared.

Answer 6

thanks @VeritasVosLiberabit I got it.

Answer 7

you're welcome