Question

Complex number equations.

Answer 1

\[(-1+i)^{3}z ^{3}=1\]

Answer 2

hint. Put bouth numbers in polar form. Later notice that 1 has argument =0

Answer 3

now argument of z^3 have to be \(-9\pi/4\), so that when added with the other gives 0. And length have to be \(1/2\sqrt2\) which is the reciprocal of the other so when multiplied gives 1

Answer 4

later just find the \(\sqrt[3]{z^3}\) to get the answer

Answer 5

got it? :)

Answer 6

It's pretty difficult to understand ):

Answer 7

Can you explain in a simpler way, please?

Answer 8

(-1+i)^3*z^3=1 Let z=x+iy So equation become (-1+i)^3*(x+iy)^3=1 or[ (-1+i)*(x+iy)]^3=1 or (-1+i)*(x+iy)=1^1/3=1 or (-x-y)+(x-y)i=1 By Comparing Real Number n Imaginary Number we get Equations -x-y=1 and x-y=0 Solving this We get x=y and Putting it Into -x-y=1 We get -x-x=1 or -2x=1 or x=-1/2 and y=-1/2 Sp Complex Number z=x+iy =( -1/2)+(-1/2)i= -1/2(x+iy) Answer 100 %

Answer 9

Thankss