How do I write 5+7+9+11+13+15+17 in sigma notation?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
What is the common factor that we are adding each time?
OpenStudy (deadshot):
2
OpenStudy (anonymous):
Right, so we're looking at something that looks like:
\[\sum Number + 2n\]
The "Number" will depend on where you want to start your summation. Usually, we begin from n = 0 or from n = 1. We'll need to make that choice now. Which would you like to do?
OpenStudy (deadshot):
n=0
OpenStudy (anonymous):
Alright, so if n = 0, and we want to get the number 5, what is our "Number?"
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (deadshot):
would it be 3?
OpenStudy (anonymous):
Not 3
We want:
Number + 2*0 = 5
OpenStudy (deadshot):
so, it would be 5? since 2*0=0
OpenStudy (anonymous):
Yep :)
OpenStudy (anonymous):
So, we now we just need to decide when to stop our summation. The last term that we want is 17. So, what is n when the result is 17?
5+2n = 17
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (deadshot):
6?
OpenStudy (anonymous):
Yep :)
And we just put it all together:
\[\sum_{n=0}^{6}5+2n = 5+7+9+11+13+15+17\]
OpenStudy (deadshot):
Thanks!
OpenStudy (anonymous):
Does it all make sense?
OpenStudy (deadshot):
yes
Still Need Help?
Join the QuestionCove community and study together with friends!