Mathematics
8 Online
OpenStudy (anonymous):
Please help me with this question! D:
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OpenStudy (anonymous):
hero (hero):
\[5^x = 26\]
Log both sides
OpenStudy (blackops2luvr):
mind blown ^.^
OpenStudy (anonymous):
Wrong one!
OpenStudy (anonymous):
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hero (hero):
Hint:
Let x = 100,000, then compute
N(100,000) = 100 + 20(ln(100,000/4)
OpenStudy (anonymous):
Is the answer 303?
OpenStudy (anonymous):
Is this correct?
OpenStudy (anonymous):
Wrong one.
hero (hero):
Yes, you computed the correct result although maybe it should be 302
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OpenStudy (anonymous):
hero (hero):
Correct
hero (hero):
How many of these questions do you have?
OpenStudy (anonymous):
Is this correct?
And many haha.
hero (hero):
You didn't solve that one correctly. 400 = B(t) and you have to solve for t.
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OpenStudy (anonymous):
How do I do that?
hero (hero):
You are given:
\(B(t) = 4e^{0.8t}\)
B(t) = 400 so
\(400 = 4e^{0.8t}\)
Solve for t
OpenStudy (anonymous):
I'm not sure how to do that...
hero (hero):
Divide both sides by 4, then log both sides.
OpenStudy (anonymous):
so.. 4.61= idk how to do that part..
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hero (hero):
Where did you get 4.61?
OpenStudy (anonymous):
400/4=100 then log it..
OpenStudy (anonymous):
It's 6 never mind..
OpenStudy (anonymous):
Is this correct?
hero (hero):
\(100 = e^{0.8t}\)
For logging remember this rule:
\(\log(a^b) = b \log(a)\)
\(\log(100) = \log(e^{0.8t})\)
\(\log(100) = t \log(e^{0.8})\)