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Mathematics 8 Online
OpenStudy (anonymous):

Please help me with this question! D:

OpenStudy (anonymous):

hero (hero):

\[5^x = 26\] Log both sides

OpenStudy (blackops2luvr):

mind blown ^.^

OpenStudy (anonymous):

Wrong one!

OpenStudy (anonymous):

hero (hero):

Hint: Let x = 100,000, then compute N(100,000) = 100 + 20(ln(100,000/4)

OpenStudy (anonymous):

Is the answer 303?

OpenStudy (anonymous):

Is this correct?

OpenStudy (anonymous):

Wrong one.

hero (hero):

Yes, you computed the correct result although maybe it should be 302

OpenStudy (anonymous):

hero (hero):

Correct

hero (hero):

How many of these questions do you have?

OpenStudy (anonymous):

Is this correct? And many haha.

hero (hero):

You didn't solve that one correctly. 400 = B(t) and you have to solve for t.

OpenStudy (anonymous):

How do I do that?

hero (hero):

You are given: \(B(t) = 4e^{0.8t}\) B(t) = 400 so \(400 = 4e^{0.8t}\) Solve for t

OpenStudy (anonymous):

I'm not sure how to do that...

hero (hero):

Divide both sides by 4, then log both sides.

OpenStudy (anonymous):

so.. 4.61= idk how to do that part..

hero (hero):

Where did you get 4.61?

OpenStudy (anonymous):

400/4=100 then log it..

OpenStudy (anonymous):

It's 6 never mind..

OpenStudy (anonymous):

Is this correct?

hero (hero):

\(100 = e^{0.8t}\) For logging remember this rule: \(\log(a^b) = b \log(a)\) \(\log(100) = \log(e^{0.8t})\) \(\log(100) = t \log(e^{0.8})\)

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