Question

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Answer 1

@SolomonZelman

Answer 2

@SolomonZelman

Answer 3

\(\LARGE\color{blue}{ \bf │2x+1│≤5 }\)

\(\Large\color{green}{ \bf 2x+1≤5 ~~~~or~~~~2x+1≥-5 }\)

\(\Large\color{green}{ \bf 2x≤4 ~~~~~~~~~~~~~~~~~~~2x≥-6 }\)

\(\Large\color{green}{ \bf x≤2 ~~~~~~~~~~~~~~~~~~~~~x≥-3 }\)

hence you get

\(\Large\color{green}{ \bf -3≤x≤2 }\)

Answer 4

so A?

Answer 5

@SolomonZelman

Answer 6

can you help me? @marissalovescats

Answer 7

No not A. A shows x<=-3 and x >=-2

You can automatically use the process of elimination to cross out C because those are open circles and since were doing with <= or >=, those are closed circles.

A cool trick for graphing inequalities is to look at the arrows or your (>= or <=)

Here as showed, he got the answers of x<=2 and x>=-3

So you put a closed circle on 2 and draw a line from 2 going to the left because is is <= so the arrow is pointing to the left. And with x>=-3 you put a closed dot on -3 and draw a line to the right of it because it is >=.

That's a cool trick I learned. Make sense? :)

Answer 8

Another trick for knowing whether to draw open or closed circles:

Open: > or <

Closed: >= or <= because you have a little something extra (aka the equal part or aka coloring in the circle)

Answer 9

um i thoght his answer said x is greater than or equal to -3 and x is less than or equal to 2

Answer 10

Well yes

-3<=x<=2 is the same thing as x<=2 and x>=-3. Putting the two separate is just easier to look at when you are wanting to graph it so you can use that arrow trick.

Answer 11

The answer is B, do you see why or do you need further explanation?

Answer 12

yes im seeing it now thank you. is it okay if i ask a few more questions ??

Answer 13

Yeah that's fine

Answer 14

@marissalovescats

Answer 15

So we know for one p>-2