Question

Could someone help me integrate the attached equation? Thanks!

Answer 1

I suggest doing a substitution, 1-x=u

Answer 2

\(\large u = 1-x\) may simplify a bit :

\[\int (2-u)^2t^5(-du)\]

Answer 3

\[\int (2-u)^2u^5(-du) ~*\]

Answer 4

ganeshie8, I keep getting (1-u)^2 and not (2-u)^2. Could you elaborate on how you got that? Thanks!

Answer 5

\(\large u = 1-x\)

\(\large \implies x = 1 - u\)
\(\large \implies x+1 = 2 - u\)

Answer 6

I follow now. Thanks!

Answer 7

yw

Answer 8

you still need to expand \((2-u)^2\), distribute it wid\(u^5\) and integrate each term... good luck !

Answer 9

and dont forget to switch back to x's in the end!

Answer 10

I definitely won't forget. Thanks!