alggebra 1 help?
@jim_thompson5910 please help me finish?!i only have three more but i only need the last part on some
post what you have so far
for part a i said no because an x value cant have two y values
is that right?
good, x = 1 corresponds to both y = 2, y = 4
so that's why it's not a function
okay cool. now my second question. ill attacht it one second
Part A: What is the solution to the pair of equations represented by p(x) and f(x)? (3 points) Part B: Write any two solutions for f(x). (3 points) Part C: What is the solution to the equation p(x) = g(x)? Justify your answer. (4 points)
i just need part c on that one^
p(x) = g(x) means that the two functions p(x) and g(x) have the same y value (for some given x value between the two) essentially, that all boils down to the point of intersection between p(x) and g(x)
specifically, they want the x value of this intersection point
(-6,1) so x=-6??
correct
x = -6 makes p(x) = g(x) true
so i only say x=-6 not the whole (x,y)?
let's come up with random equations for p(x) and g(x) let's say p(x) = 2x, g(x) = 3-x so when we say p(x) = g(x) we really mean 2x = 3 - x the solution to that will be x = some number which is the same solution to p(x) = g(x)
so you can see they only care about x = -6
awesome sounds easier now(= heres my last question that i need part a,b,c help on if thats okay
Part A: Using the graph above, create a system of inequalities that only contain points C and F in the overlapping shaded regions. Explain how the lines will be graphed and shaded on the coordinate grid above. (5 points) Part B: Explain how to verify that the points C and F are solutions to the system of inequalities created in Part A. (3 points) Part C: Natalie can only attend a school in her designated zone. Natalie's zone is defined by y < -2x + 2. Explain how you can identify the schools that Natalie is allowed to attend. (2 points)
there are an infinite number of ways to tackle part A, but the easiest I see is to find two inequalities that overlap in the first quadrant
okay so we just make up our own two?
yep, that is correct
how do you go about doing that though? obviously they both would have to be greater than?
in the first quadrant, what set of x values are allowed?
possitive numbers? greater then 1 ??
why not greater than 0?
so x > 0 what about y?
y can also be greater than zero or 1 right?
y > 0
put together, x > 0 y > 0 they both define the 1st quadrant
they both need to be true to be in the right quadrant
right
that's not the only possible system, but probably the easiest to spot
okay so for the first equation ?
you're dealing with inequalities, not equations
oh okay sorry i forgot
hopefully you see how I got that system
so i can use those as my system of inequalities?
you can, but it's not the only one you can use
do you see how the system works? how it graphs to overlap in just the 1st quadrant
it says they can only inclue the points C and F do they include E?
Yes i do understand no how it works(=
where are you getting E? I thought it was just C and F
It is im just making sure they dont include E
oh, I don't see E, so I don't think E is part of what they want
does x is greater than 0 pass through C?
what is the x coordinate of point C?
x=2
does that make x > 0 true ?
yes
okay im seeing it now.
thank you sos much for your help(=
do the same for the y coordinate of C
and you'll find it makes y > 0 true as well
you repeat that for any point you want to test
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