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can u simplify 5/3x^2 y - 4/6xy^3. yes or no if no explain why.
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This? \(\dfrac{5}{3x^2y} - \dfrac{4}{6xy^3} \)
yes
First, the second fraction can be reduced since both the numerator and denominator are divisible by 2.
Second, the fractions can be subtracted by first finding a common denominator.
I simplified it to: \[\frac{ (5y^2-2x) }{ (3x^2y^3) }\]
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thanks guys
ǝɯoɔlǝʍ ǝɹ,noʎ :)
\(\dfrac{5}{3x^2y} - \dfrac{4}{6xy^3}\) \(= \dfrac{5}{3x^2y} - \dfrac{2}{3xy^3} \) \(= \dfrac{5y^2}{3x^2y^3} - \dfrac{2x}{3x^2y^3} \) \(= \dfrac{5y^2 - 2x}{3x^2y^3} \)
Thanks @mathstudent55
thanks mathstudent55
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yw
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