Question

Partial pressure and equilibrium questions!!

Answer 1

this is the question
pleeeeeeeeeeease help

Answer 2

@Kainui

Answer 3

@Kainui help plzzz

Answer 4

@emcrazy14

Answer 5

The question says that 20% of the steam has been converted, right?
This means that at equilibrium, there would be 20% hydrogen present since the molar ratio of H2O and H2 is 2:2= 1:1.
10% oxygen will be present since the molar ratio of H2O and O2 is 2:1.
And 100-20=80% of steam i.e H2O will be present since 20% has been converted into products.

The total no of moles at equilibrium would be the sum of the moles of all these gases i.e 20%+80%+10%= 110% = 110/100= 1.1

So now you can express the partial pressure for each component as given in the answer.
Partial pressure for H2O= \[\frac{ no. of moles of H2O }{total no. of moles } \times total pressure\]

Answer 6

They have given the total pressure i.e 1 atm in the question.

Answer 7

So your answer for H2O would be
\[\frac{ 0.8 }{ 1.1 } \times 1\]

Answer 8

You can do it in the same way for O2 and H2.

Answer 9

Lol Kainui

Answer 10

its's so unfortunate >xD
Your timing

Answer 11

lmao i guess i have bad luck with u @Kainui

Answer 12

We're sorry O_O
Didn't mean to offend @Kainui

Answer 13

hehe but well thnx guys!!! @emcrazy14 and @Kainui :)