what is the integral of f(x) when

f(x)=sqrt((3-x)/(x+1))

please show all steps

thank you!!

Question

what is the integral of f(x) when

f(x)=sqrt((3-x)/(x+1))

please show all steps

thank you!!

chris911 · Answer

lol wassup its early O,O

anonymous · Answer

what is the integral of f(x) when

f(x)=sqrt((3-x)/(x+1))

please show all steps

thank you!!

anonymous · Answer

@AccessDenied 
@mathavraj 
@Hero
@SolomonZelman

anonymous · Answer

@mathavraj

anonymous · Answer

@SolomonZelman

solomonzelman · Answer

I am not good at integrating (yet) -:(

anonymous · Answer

@AccessDenied

anonymous · Answer

@ganeshie8

anonymous · Answer

someone help

anonymous · Answer

i think u have to do it by substitution method

solomonzelman · Answer

idk, I would guess you multiply top and bottom times √(x+1) to rationalize the denominator. Will see what accessdenied says....

accessdenied · Answer

I am imagining an interesting u-substitution.  If you chose u = sqrt(x + 1), you could use some algebra to put this in terms of sqrt(3 - x) equaling a function of u.  And taking the du part will give you what is in the denominator as well.  Can you see what I am going for here?  And if so, what do you get by trying that route?

anonymous · Answer

:/

anonymous · Answer

@hartnn

anonymous · Answer

seond one

anonymous · Answer

ty one more question

parthkohli · Answer

Weren't you in 8th?

anonymous · Answer

@ParthKohli 

THAT WAS MY YOUNGER BROTHER QUESTION
HE USES MY ACCOUNT

hartnn · Answer

i am not sure how u= u=x+1 would work...

i was thinking more on the lines of 
$\Large \dfrac{3-x}{\sqrt{(3-x)(x+1)}}$

then separate the denominator

hartnn · Answer

no, don't separate the denominator....

hartnn · Answer

arrange the numerator in terms of the DERIVATIVE of denominator 

and then separate it out

anonymous · Answer

THX
now answwer my younger brothers question

hartnn · Answer

whats your younger bro's question ?

anonymous · Answer

the present age of mr jackson son is in the ratio 17:9
if the ratio 9 years ago was 7:3 find there present age

anonymous · Answer

its a ratio sum

hartnn · Answer

let their present age be x and y

ratio = 17/9
so
x/y = 17/9

hartnn · Answer

after 9 years...
their ages will be 
x+9
y+9

hartnn · Answer

ratio then will be
(x+9)/(y+9)  =7/3

now you have 2 equations 2 unknowns

anonymous · Answer

ty
@hartnn

marissalovescats · Answer

How is it set up? 

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