Find the indicated limit, if it exists. limit of f of x as x approaches 0 where f of x equals 5 x minus 8 when x is less than 0 and the absolute value of the quantity negative 4 minus x when x is greater than or equal to 0
f(x)=5x-8 } x<0 f(x)=4-x } x>0
like that?
oh -4 sry
f(x)=5x-8 } x<0 f(x)=|-4-x| } x>0
the limt DNE
since the value f(0-) != f(0+)
the values left of zero are not equal to the value at just right of zero
okay these are y answer choices -4 -12 -8 The limit does not exist. @dan815
okay so these are the rules
the limit doesnt exist at the point x=0 if from the left size of 0 you approach a different number as from left side
you mean that if from one side of 0 the limit approaches one number and from the other side of 0 the limit approaches a different number, than the limit doesn't exist.
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