Find the indicated limit, if it exists.
limit of f of x as x approaches 0 where f of x equals 5 x minus 8 when x is less than 0 and the absolute value of the quantity negative 4 minus x when x is greater than or equal to 0
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (dan815):
f(x)=5x-8 } x<0
f(x)=4-x } x>0
OpenStudy (dan815):
like that?
OpenStudy (dan815):
oh -4 sry
OpenStudy (dan815):
f(x)=5x-8 } x<0
f(x)=|-4-x| } x>0
OpenStudy (dan815):
the limt DNE
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (dan815):
since the value f(0-) != f(0+)
OpenStudy (dan815):
the values left of zero are not equal to the value at just right of zero
OpenStudy (anonymous):
okay these are y answer choices
-4
-12
-8
The limit does not exist.
@dan815
OpenStudy (dan815):
okay so these are the rules
OpenStudy (dan815):
the limit doesnt exist at the point x=0 if from the left size of 0 you approach a different number as from left side
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (solomonzelman):
you mean that if from one side of 0 the limit approaches one number and from the other side of 0 the limit approaches a different number, than the limit doesn't exist.