HELP, not strong in math: f'x=ln(1-ln(x))

Question

HELP, not strong in math:  f'x=ln(1-ln(x))

shubhamsrg · Answer

Need to find f(x) ? Integration ?

anonymous · Answer

Sorry, new to "open study"
The function is fx=ln(1-lnx)        I need to find the f' then solve for zero to find critical points.

anonymous · Answer

maxima minima u mean

anonymous · Answer

yes

shubhamsrg · Answer

you are having problems in applying the chain rule ?

anonymous · Answer

Well, my best guess so far has been 1/(1-lnx) *1.  And I think that is correct, but not sure how to solve for zero from here?

shubhamsrg · Answer

1/(1-lnx) part is correct. WIth that you need to multiple the derivative of (1-lnx) too.
So there is a mistake in your derivative. Please re-check.

anonymous · Answer

Applying the chain rule to the inside (1-ln x) would be one, yes? The 1 would be zero, then would not the "x" in the remaining ln x be "1" or 1/x?

shubhamsrg · Answer

D(1-lnx) = -1/x 
:|

anonymous · Answer

So the derivative of fx=ln(1-ln x) would be:

1/(1-lnx) * -1/x             ?

shubhamsrg · Answer

Yes.

anonymous · Answer

Thank you, another silly question then, how would the fractions line up?

shubhamsrg · Answer

Didn't get your query ?

anonymous · Answer

|dw:1401114137943:dw||dw:1401114412380:dw|
trying to insert a drawing of the Equation.