Question

find the sum to n term
1/(1*4)+1/(4*7)+1/(7*10)+..........

Answer 1

Can you figure out the nth term ?

Answer 2

1/(n(n+3))

Answer 3

1/(3n+1)(3n+4)
and n start from zero

Answer 4

nop, that'll only give you the first term of the sequence.
Note that there are two separate sequences
1,4,7,10..
and 4,7,10,13..
you should find nth terms in both.

Answer 5

sorry

Answer 6

wow Indians are fr good at math..

Answer 7

plz tell me the n th term

Answer 8

Now you your nth term.
1/(3n+1)(3n+4)
Will it be alright if I express the numerator as ( (4+3n)-(1+3n) )/3 ?
Please observe this expression carefully.

Answer 9

@BSwan already did :|

Answer 10

sorry coue im rushing :)
i let u do the jop ;)

Answer 11

sorry u can write numerator as ur second expression

Answer 12

See my main aim is to break 1/(3n+1)(3n+4) into partial fractions.
For that purpose, I noticed the difference between the 2 factors in the denominator.
(4+3n) - (3n+1) = 3
We get a constant, which is good.
So far so good ?

Answer 13

1/(3*(3n+1))-1/(3*(3n+4))

Answer 14

then?

Answer 15

@shubhamsrg

Answer 16

helloo @shubhamsrg

Answer 17

i m in the middle of my math @shubhamsrg

Answer 18

I am sorry, had to go.
Are you there?