Question

integral question :)

Answer 1

\[\large \int\limits_{0}^{?} \large \frac{d\theta}{1+\frac{1}{2}\cos \theta}\]

Answer 2

1 = sin^2 + cos^2 may help...

Answer 3

no x(

Answer 4

ok idk if it work lol

Answer 5

it looks really familiar

Answer 6

did u try u subs

Answer 7

how about multiply top and bottom by conjugate

Answer 8

then using 1=sin^2w+cos^2w

Answer 9

well i tried , doing it using complex number mmm
and i got an answer ,
i wanna solve it normally
:O for high school student :\
so nothing real worked with me :\

Answer 10

ya i wud do complex too

Answer 11

but i knew u were highschool

Answer 12

http://math.stackexchange.com/questions/134577/how-do-you-integrate-int-frac1a-cos-x-dx

Answer 13

i got an answer of
4 pi /sqrt 3

Answer 14

lol if bswan is in highschool then i wud be in elementary or kg >.<

Answer 15

dan im not high school lol
im teaching a high school student :)

Answer 16

ohh okk sry

Answer 17

so i wont solve it using complex :(

Answer 18

parts!!?! long but its gotta work

Answer 19

1=sin^2(x/2)+cos^2(x/2)
and then
cosx=cos^2(x/2)-sin^2(x/2)

Answer 20

what are u gonna do with that?

Answer 21

thx @ganeshie8 for the link
i think i got a suitable method

Answer 22

\[\int \dfrac{d\theta}{1+\frac{1}{2}\cos \theta} = \int \dfrac{d\theta}{1+\frac{1}{2}(2\cos ^2(\theta/2) - 1)} = \dfrac{d\theta}{\cos^2(\theta / 2) + \frac{1}{2}}\]

Answer 23

divide top and bottom by cos^2 and substitute \(u = \tan (\theta/2)\)

Answer 24

cool :)

Answer 25

what i did is this ,
z=e^itheta
so the integral was like this