Question

Find the axis of symmetry for y = 4x^2 + 16x - 2

Answer 1

do you know to do complete square method ?

Answer 2

test -1 (-b/2a) = -16/2*4=-1

Answer 3

The axis of symmetry would be found by -b/ 2a... have a try now please,,,,

Answer 4

The axis of symmetry is just the vertical line passing through the vertex. In other words, since the vertex has coordinates \(\left(-b/2a, f(-b/2a)\right)\), you have the axis of symmetry as the line \(x = -b/2a\). Don't forget to include "\(x = \)"

Answer 5

Do I use the formula ax^2 + bx + c =0

Answer 6

Is the answer -8?

Answer 7

Is it really?

Answer 8

nope -18

Answer 9

you could just use the equation givenby @ParthKohli

Answer 10

I did.

Answer 11

or go for complete square method, which i assume is not necassary if you can do it a simple way

Answer 12

show me your working

Answer 13

16x/2

Answer 14

x=-8

Answer 15

x = -b/2a
b = 16 a = 4

Answer 16

UGH
This ish is so frustrating.

Answer 17

why dont u substitute for a and b and find x :/ not so hard as think