fx=x sqrt of(6-x) looking for f'??

Question

fx=x sqrt of(6-x)   looking for f'??

yttrium · Answer

Do you know product rule?

anonymous · Answer

yes, that is what I was thinking.

yttrium · Answer

Well you can use that.

anonymous · Answer

Would you convert the sqrt to 6-x ^1/2??

anonymous · Answer

And use the power rule?

yttrium · Answer

Well conversion and power rule will also do.
Look at this: By converting the whole expression to a single power:
$$f(x) = \sqrt{6x^2 - x^3} = (6x^2 - x^3)^{\frac{ 1 }{ 2 }}$$

yttrium · Answer

^now you can use power rule there

anonymous · Answer

Outstanding, let me work on this,  Thank you!!

yttrium · Answer

Okay. Good luck. :)

anonymous · Answer

Help again, how did you get those values.  Can you break it down for me.

yttrium · Answer

What values are you talking about?

anonymous · Answer

$$fx=x \sqrt{6-x}$$
This is what I started with.  Did you multiply the x into the radical.  Don't you need to multiply radical w/ radical?  not sure of this part.

anonymous · Answer

$$x ^{1}*6-x ^{1/2}?$$

yttrium · Answer

aah okay. let have one basic example
$$\sqrt{x^2} = x $$
so if you wanna convert x into radical form, you'll make it squared
so in that case:
$$f(x) = \sqrt {x^2 (6-x)}$$
hence
$$f(x) = \sqrt { 6x^2 - x^3}$$

anonymous · Answer

You are the bomb.  Thanks.  How does the medals thing work here?