Question

What is the radius of the circle (x-2)^2+(y+3)^2=6

Answer 1

\(\Large\color{blue}{ \bf (x-h)^2+(y-k)^2=r^2 }\)

Answer 2

(h,K) is the center. r is the radius. Compare your equation to the blue.

Answer 3

So is the radius 6 or 36?

Answer 4

but in your case, from the comparison, you can see that \(\large\color{blue}{ \bf 6=r^2 }\)

Answer 5

So r = ?

Answer 6

6

Answer 7

close
r^2=6
r=±√6

but in your case just √6 (and not -√6 ) because radius is distance and can't be negative.

Answer 8

Ohhhh okay thank you! Since you are here can you really quick help me out with another.
Find the center and the radius of the circle: x^2+y^2-12x+6y=19

Answer 9

@SolomonZelman

Answer 10

x^2+y^2-12x+6y=19
x^2-12x+y^2+6y=19
x^2-12x+36+y^2+6y=19+36
x^2-12x+36+y^2+6y+9=19+36+9
(x-6)^2+(y+3)^2=64
(x-6)^2+(y+3)^2=8^2

Answer 11

compare to

(x-h)^2+(y-k)^2=r^2

Answer 12

Is the answer center (-6,3) and radius 64?

Answer 13

@SolomonZelman

Answer 14

the other way (6,-3)
and the radius is 8

Answer 15

Thank you so much!