Question

solve using the quadratic equation-imaginary roots
x^2-10x+34

Answer 1

use the quadratic formula

Answer 2

Step 1 :

Simplify x2+10x + 34

Answer 3

@eHoaX yea iknow i got to the part of \[110 \pm \sqrt{-116}\div 2\]

Answer 4

sqrt of a negative turns into an i for imaginary then you proceed as normal

Answer 5

\[(-b+/-\sqrt{(b)^2-4ac})/(2a)\]

Answer 6

wait using quadratic formula here omg !

Answer 7

\[\frac{ 10+/-\sqrt{100-136} }{ 2 }\]

Answer 8

i think either way works @Shay17

Answer 9

Solving x2+10x+34 = 0 by the Quadratic Formula .

According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :

- B ± √ B2-4AC
x = ————————
2A

Answer 10

\[\frac{ 10+/-\sqrt{-36} }{ 2 }\]

Answer 11

\[\frac{ 10+/-6i }{ 2 }\]

Answer 12

A = 1
B = 10
C = 34
B2 - 4AC = 100 - 136 = -36

Answer 13

\[5+3i, 5-3i\]

Answer 14

Applying the quadratic formula :

-10 ± √ -36
x = ——————
2

Answer 15

any more help @a$apkillah

Answer 16

√ -36 =
√ 36 • (-1) =
√ 36 • √ -1 =
± √ 36 • i

Can √ 36 be simplified ?

Answer 17

Yes so ..
√ 36 = √ 2•2•3•3 =2•3•√ 1 =
± 6 • √ 1 =
± 6

Answer 18

okay im good i think i understand i messed up thats why thanks @Shay17 and @eHoaX

Answer 19

So now we are looking at
x = ( -10 ± 6i ) / 2

x =(-10+√-36)/2=-5+3i= -5.0000+3.0000i
or
x =(-10-√-36)/2=-5-3i= -5.0000-3.0000i

Answer 20

Yw ..

Answer 21

ima give u a medal @Shay17 and then can u give @eHoaX one so its een since u guys both helped

Answer 22

even*