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Mathematics 8 Online
OpenStudy (anonymous):

HeLp On ThIs QuAdRaTiC PleAsE

OpenStudy (anonymous):

If alpha and beta are the roots of the equation ax^2 + bx + c=0 find the equation whose roots are alpha +2 , Beta +2

OpenStudy (mertsj):

If alpha and beta are roots then a(x-alpha)(x-beta)=0

OpenStudy (anonymous):

yes

OpenStudy (mertsj):

For the new equation, a[x-(alpha+2)]{x-(beta+2)]=0

OpenStudy (anonymous):

the equation given is ax^2 - (4a - b)x + (4a - 2b + c)

OpenStudy (anonymous):

@satellite73 will u help me

OpenStudy (anonymous):

Please don't go if you know the answer

OpenStudy (anonymous):

some algebra i think lets see if we can figure it out

OpenStudy (anonymous):

\[ax^2 + bx + c=0\] roots are \(\alpha, \beta\) so \[\alpha +\beta=-\frac{b}{a}\] \[\alpha\beta=\frac{c}{a}\]

OpenStudy (anonymous):

let's see

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

for the new one the roots are \[\alpha +2,\beta+2\] so \[\alpha +2+\beta+2=\alpha +\beta +4\]

OpenStudy (anonymous):

\[=\frac{-b}{a}+4\]

OpenStudy (anonymous):

and \[\alpha +2)(\beta+2)=\alpha \beta +2\alpha +2\beta +4=\frac{c}{a}-2\frac{b}{a}+4\]

OpenStudy (anonymous):

that should do it i hope

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