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Mathematics
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OpenStudy (anonymous):
HeLp On ThIs QuAdRaTiC PleAsE
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OpenStudy (anonymous):
If alpha and beta are the roots of the equation ax^2 + bx + c=0 find the equation whose roots are alpha +2 , Beta +2
OpenStudy (mertsj):
If alpha and beta are roots then a(x-alpha)(x-beta)=0
OpenStudy (anonymous):
yes
OpenStudy (mertsj):
For the new equation, a[x-(alpha+2)]{x-(beta+2)]=0
OpenStudy (anonymous):
the equation given is
ax^2 - (4a - b)x + (4a - 2b + c)
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OpenStudy (anonymous):
@satellite73 will u help me
OpenStudy (anonymous):
Please don't go if you know the answer
OpenStudy (anonymous):
some algebra i think
lets see if we can figure it out
OpenStudy (anonymous):
\[ax^2 + bx + c=0\] roots are \(\alpha, \beta\) so
\[\alpha +\beta=-\frac{b}{a}\]
\[\alpha\beta=\frac{c}{a}\]
OpenStudy (anonymous):
let's see
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
for the new one the roots are
\[\alpha +2,\beta+2\] so \[\alpha +2+\beta+2=\alpha +\beta +4\]
OpenStudy (anonymous):
\[=\frac{-b}{a}+4\]
OpenStudy (anonymous):
and \[\alpha +2)(\beta+2)=\alpha \beta +2\alpha +2\beta +4=\frac{c}{a}-2\frac{b}{a}+4\]
OpenStudy (anonymous):
that should do it i hope
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