Question

In a certain population of elephants, 125 are gray, 50 are grayish-brown, and 25 are brown. The allele for gray is G, the allele for brown is g, and these two alleles show incomplete dominance relative to each other.

What is the frequency of the g allele in the existing population?
Answer
a.
0.75
b.
0.5
c.
0.25
d.
0.125

Answer 1

Also,

What is the expected frequency of grayish-brown elephants in the next generation if the population is at Hardy-Weinberg equilibrium?
Answer
a.
0.75
b.
0.375
c.
0.25
d.
0.188

Answer 2

I have my answers, just want to make sure I did them right.

Answer 3

1-b

Answer 4

C

Answer 5

first one C?

Answer 6

First one I got C because (25x2) + (50) / 400 = .25?

Answer 7

no...1-b and then 2;c

Answer 8

ok wait

Answer 9

@nincompoop

Answer 10

@wolfe8

Answer 11

yes sorry for that, 1-c

Answer 12

ok, can you show me how you got the second one.

Answer 13

wait..

Answer 14

for 2 it would be A

Answer 15

it would be 2pq...where p and q are the frequencies of G and g

Answer 16

????????

Answer 17

I figured it out, I'm dumb lol. @abhisar

Firs the second equation you need to find both frequency.
to find frequency of G, you would take 125 (GG) (125x2(2 G alleles are present) + (50 (Gg has one allele so you would only take 50 instead of 50x2) / 400 Because in one gene for example GG there are two alleles here present, so instead of dividng by 200, we divide by 400 = .75

Do the same thing to the g allele, g allele is in Gg and in gg, so in gg we get 50, so (50x2 (Because we have 2 allele of 'g' in gg)) + (50 (Because we have one allele 'g' in Gg)) /400 = .25

we know we did this right if our final = 1 so lets check our math

.75 + .25 = 1 <----- awesome

now to find the frequency we need to plug into equation 2pq. P = dominate (G) q = recessive (g) = 2 (.75) (.25) = .375

:)

Answer 18

oh man i was half crrct.....LOL...it looks as i was dumb..!!

Answer 19

i cant believe i said the crrct way..but was not myself able to follow it..!!