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Mathematics 8 Online
OpenStudy (anonymous):

plz help ..

OpenStudy (anonymous):

@Ashleyisakitty @alphadxg @annas @mathslover @hartnn @merchandize

hartnn (hartnn):

which one ?

OpenStudy (anonymous):

first 3

hartnn (hartnn):

whats \(\large 1+tg^2 x=...?\) know any pythagorean identity which can simplify this ?

OpenStudy (anonymous):

no..

hartnn (hartnn):

seems like you need to brush up your trigonometric formulas before taking up integration list all/any pythagorean identity you know .... or find out!

OpenStudy (anonymous):

okie

OpenStudy (anonymous):

1+tg2x= tgx rite?

hartnn (hartnn):

is it tg x ?? isn't it \(\Large 1+tg^2x = \sec^2 x \) ?

OpenStudy (anonymous):

noo

hartnn (hartnn):

tg is tangent ratio , right ?

OpenStudy (anonymous):

can u solve me this .. i want just ans ..

hartnn (hartnn):

i guess, you have been here long enough to know that i do not give just answers.... use this formula in 1st integral, \(1+tg^2x = \sec^2x\) then substitute t= tg x find dt. and make a new integral in just 't'

OpenStudy (anonymous):

okk

hartnn (hartnn):

that new integral in just 't' would be very easy to solve....try it :)

OpenStudy (dan815):

which one are we on now

OpenStudy (anonymous):

1st 1

OpenStudy (dan815):

okay so with respect to dx all the other variables are constant im assuming, since they didnt say they are a function of x

hartnn (hartnn):

dan tg x mean tan x

OpenStudy (dan815):

ohh

OpenStudy (dan815):

okay so tell us when u finish doing what hartnn said

OpenStudy (dan815):

kai o kan 5 goku

hartnn (hartnn):

lol and you can take over with 1st one too, i won't mind

OpenStudy (anonymous):

m busy to doing other integralss

OpenStudy (dan815):

is that u in a saree

OpenStudy (anonymous):

sorry?

OpenStudy (dan815):

nevermind

OpenStudy (anonymous):

k

hartnn (hartnn):

and i am the one in my profile pic too, i am actually goku :P

OpenStudy (dan815):

you always do have a goku pic

OpenStudy (dan815):

i used to be crazy about that show once up a time

OpenStudy (anonymous):

|dw:1401165940520:dw| @dan815 solve it

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