whats
\(\large 1+tg^2 x=...?\)
know any pythagorean identity which can simplify this ?
OpenStudy (anonymous):
no..
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hartnn (hartnn):
seems like you need to brush up your trigonometric formulas before taking up integration
list all/any pythagorean identity you know ....
or find out!
OpenStudy (anonymous):
okie
OpenStudy (anonymous):
1+tg2x= tgx
rite?
hartnn (hartnn):
is it tg x ??
isn't it
\(\Large 1+tg^2x = \sec^2 x \)
?
OpenStudy (anonymous):
noo
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hartnn (hartnn):
tg is tangent ratio , right ?
OpenStudy (anonymous):
can u solve me this ..
i want just ans ..
hartnn (hartnn):
i guess, you have been here long enough to know that i do not give just answers....
use this formula in 1st integral,
\(1+tg^2x = \sec^2x\)
then substitute
t= tg x
find dt.
and make a new integral in just 't'
OpenStudy (anonymous):
okk
hartnn (hartnn):
that new integral in just 't' would be very easy to solve....try it :)
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OpenStudy (dan815):
which one are we on now
OpenStudy (anonymous):
1st 1
OpenStudy (dan815):
okay so with respect to dx all the other variables are constant im assuming, since they didnt say they are a function of x
hartnn (hartnn):
dan
tg x mean tan x
OpenStudy (dan815):
ohh
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OpenStudy (dan815):
okay so tell us when u finish doing what hartnn said
OpenStudy (dan815):
kai o kan 5 goku
hartnn (hartnn):
lol
and you can take over with 1st one too, i won't mind
OpenStudy (anonymous):
m busy to doing other integralss
OpenStudy (dan815):
is that u in a saree
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OpenStudy (anonymous):
sorry?
OpenStudy (dan815):
nevermind
OpenStudy (anonymous):
k
hartnn (hartnn):
and i am the one in my profile pic too, i am actually goku :P
OpenStudy (dan815):
you always do have a goku pic
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